Given the points:
(x1, y1) = (-12, 1)
(x2, y2) ==> (-8, 6)
To find the slope, use the slope formula below:
[tex]m=\frac{y2-y1}{x2-x1}[/tex][tex]\begin{gathered} m=\frac{6-1}{-8-(-12)}=\frac{6-1}{-8+12} \\ \\ m=\frac{5}{4} \end{gathered}[/tex]The slope of the line is:
[tex]\frac{5}{4}[/tex]If the order of the points is reversed, let's find the slope.
First swap the order of the points:
(x1, y1) ==> (-8, 6)
(x2, y2) ==> (-12, 1)
[tex]\begin{gathered} m=\frac{1-6}{-12-(-8)}=\frac{1-6}{-12+8} \\ \\ m=\frac{-5}{-4} \\ \\ m=\frac{5}{4} \end{gathered}[/tex]Therefore, if the order of the points is reversed, the slope will still be the same.
ANSWER:
[tex]\frac{5}{4}[/tex]If the order of the points is reversed, the slope will remain the same.