We have
diameter of the candle= d=4 inches
heigth of the candle= h= 7 inches
we have a cylinder the formula for the surface area of a cylinder is
[tex]SA=2\pi r^2+2\pi rh[/tex]where
h=heigth=7 inches
r is half of the diameter
r=4/2=2 inches
then we substitute the values in the formula
[tex]\begin{gathered} SA=2\pi(2)^2+2\pi(2)(7) \\ \end{gathered}[/tex][tex]SA=8\pi+28\pi=36\pi=113.09\approx113.1[/tex]the surface area of the candle rounded to the nearest tenth is 113.1 square inches
