Write in slope-intercept form;
[tex]\begin{gathered} 5x+10=-2y \\ \text{Make y the subject of the equation;} \\ 2y=-5x-10 \\ \text{Divide both sides by 2} \\ y=\frac{-5x-10}{2} \\ y=\frac{-5x}{2}-\frac{10}{2} \\ y=-\frac{5}{2}x-5 \end{gathered}[/tex]The slope intercept form of the line is therefore;
y = -5/2x - 5
