Given a line l, if the following points
[tex]\lbrace(x_1,y_1),(x_2,y_2)\rbrace[/tex]belongs to the line l, the slope m of this line is given by the following formula
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Using this formula in our problem, we have
[tex]m=\frac{(-7)-(-1)}{(6)-(4)}=\frac{-7+1}{6-4}=\frac{-6}{2}=-3[/tex]The slope of our line is - 3.
The slope intercept form is
[tex]y=mx+b[/tex]where m represents the slope and b the y-intercept.
We already calculated the slope, if we substitute its value on this form and evaluate one of the points, we can solve the equation for b.
[tex]\begin{gathered} (-1)=(-3)(4)+b \\ -1=-12+b \\ b=11 \end{gathered}[/tex]Our line equation is
[tex]y=-3x+11[/tex]