Let's assume that a certain line passes through the point (a,b) and has a slope m. Then its equation in point-slope form is:
[tex]y-b=m(x-a)[/tex]In this case we are told that the line passes through the point (-4,-1) and that its slope is -2 so we just need to take m=-2, a=-4 and b=-1 in the equation above to obtain the equation of this line:
[tex]\begin{gathered} y-(-1)=-2(x-(-4)) \\ y+1=-2(x+4)=-2x-8 \\ y=-2x-9 \end{gathered}[/tex]In order to graph it we need at least two of its points. We already have one, (-4,-1) and we can use its equation to find the other one. We can take x=-2:
[tex]\begin{gathered} y=-2\cdot(-2)-9=4-9 \\ y=-5 \end{gathered}[/tex]So the line also passes through the point (-2,-5).
AnswerKnowing that it passes through (-4,-1) and (-2,-5) we have the following graph: