Answer:
Given function is,
[tex]f\mleft(x\mright)=3x^2-4x+1[/tex]To find the average rate of change of f on [-3, 2]
we know that, average rate of change of a function a on the two points x=a and x=b is,
[tex]=\frac{f(b)-f(a)}{b-a}[/tex]Using this we get,
Average rate of change is,
[tex]=\frac{f(2)-f(-3)}{2-(-3)}[/tex][tex]=\frac{3(2)^2-4(2)+1-(3(-3)^2-4(-3)+1)}{5}[/tex][tex]=\frac{3(4)-8+1-3(9)-12-1}{5}[/tex][tex]=\frac{-35}{5}[/tex][tex]=-7[/tex]Average rate of change is -7
Answer is: -7