Question

Find the perimeter of the equilateral triangle h = 6x + 8 b = 12x - 4

Answer 1

Find the perimeter of the equilateral triangle h = 6x + 8 b = 12x - 4​

Perimeter = 3*L (equilateral triangle)

Pythagoras theorem

$H^2=C1^2+C2^2$

$L^2=H^2^{}+(L/2)^2$

$L^2-\mleft(L/2\mright)^2=H^2$

So we need to determine H

6x +8b = 12x - 4

12x-6x= 8b-