Given that Megan is standing on a point that is 40°16' N, coverting Megan's bearing to degree gives
[tex]\begin{gathered} 40^{\circ}16^{\prime}N=40^{\circ}\text{ + (}\frac{\text{16}}{60})^{\circ} \\ =\text{ 40 + 0.}267 \\ =40.267^{\circ}\text{ N} \\ Note\colon1^{\circ}\Rightarrow60^{\prime} \end{gathered}[/tex]
On the same line of longitude as Megan, Sarah is at 39°20' N. Similarly, converting her bearing to degree gives
[tex]\begin{gathered} 39^{\circ}20^{\prime}N=39^{\circ}\text{ + (}\frac{20}{60})^{\circ} \\ =39+0.333 \\ =39.333^{\circ}\text{ N} \end{gathered}[/tex]
Thus, we have the bearings of Megan and Sarah to be as shown below:
In the above diagram, Megan is at the East of Sarah.
Hence, for Megan to join Sarah, she (Megan) must travel in the West direction.
The correct option is D.
