The point-slope form of the equation of the line is
[tex]y-b=m(x-a)[/tex]where
[tex]\begin{gathered} m=\frac{6-(-2)}{3-1} \\ m=\frac{8}{2} \\ m=4 \end{gathered}[/tex]Replacing m=4 and the point (1,-2) we have
[tex]\begin{gathered} y-(-2)=4(x-1) \\ y+2=4x-4 \\ y=4x-6 \end{gathered}[/tex]This equation can be writen in diferent ways l