Question

8. A - If a square has a length of 4x - 2y, what is its area?

Answer 1

Answer:

$(16x^2-16xy+4y^2)\text{ square units}$

Explanation:

Given any square with side length s:

$\text{Area}=s^2$

If the side length, s=4x-2y

$\text{A}=(4x-2y)^2^{}$

Next, we expand:

$\begin{gathered} A=(4x-2y)(4x-2y) \\ =16x^2-8xy-8xy+4y^2 \\ A=(16x^2-16xy+4y^2)\text{ square units} \end{gathered}$

Its area is (16x²-16xy+4y²) square units.