We are given the following system of equations
[tex]\begin{gathered} 5x+2y=29 \\ 5x-2y=41 \end{gathered}[/tex]
Let us solve the system of equations.
Add the two equations.
[tex]\begin{gathered} 10x=70 \\ x=\frac{70}{10} \\ x=7 \end{gathered}[/tex]
Now substitute this value of x into any of the two equations to get the value of y
[tex]\begin{gathered} 5(7)+2y=29 \\ 35+2y=29 \\ 2y=29-35 \\ 2y=-6 \\ y=\frac{-6}{2} \\ y=-3 \end{gathered}[/tex]
Therefore, the solution of the system of equations is (7, -3)
x = 7
y = -3
