Respuesta :

Given:

[tex]\begin{gathered} \text{Side(IJ)}=6 \\ \angle K=90^{\circ} \\ \angle J=42^{\circ} \end{gathered}[/tex]

As, it is right angled triangle.

[tex]\begin{gathered} \text{Side JK=side IJ}\cdot\cos (42^{\circ}) \\ =6\cdot(0.7431) \\ =4.4586 \end{gathered}[/tex]

So, the side JK=4.5 ( nearest to tenth)

RELAXING NOICE
Relax