To find the lengths of the four-line segments as you know the endpoints of each segment you use the next formula (formula to find the distance between two points):
[tex]d=\sqrt{(x_2-x_1)\placeholder{⬚}^2+(y_2-y_1)\placeholder{⬚}^2}[/tex]
Segment KL:
[tex]\begin{gathered} KL=\sqrt{(3-1)\placeholder{⬚}^2+(5.5-4.5)\placeholder{⬚}^2} \\ KL=\sqrt{2^2+1^2} \\ KL=\sqrt{4+1} \\ KL=\sqrt{5} \end{gathered}[/tex]
Segment LM:
[tex]\begin{gathered} LM=\sqrt{(5-3)\placeholder{⬚}^2+(6.5-5.5)\placeholder{⬚}^2} \\ LM=\sqrt{2^2+1^2} \\ LM=\sqrt{4+1} \\ LM=\sqrt{5} \end{gathered}[/tex]
Segment PO:
[tex]\begin{gathered} PO=\sqrt{(3-1)\placeholder{⬚}^2+(3-1.66)\placeholder{⬚}^2} \\ PO=\sqrt{2^2+1.34^2} \\ PO=\sqrt{4+1.7956} \\ PO=\sqrt{5.7986} \end{gathered}[/tex]
Segment ON:
[tex]\begin{gathered} ON=\sqrt{(5-3)\placeholder{⬚}^2+(4.33-3)\placeholder{⬚}^2} \\ ON=\sqrt{2^2+1.33^2} \\ ON=\sqrt{4+1.7689} \\ ON=\sqrt{5.7689} \end{gathered}[/tex]
Part C:
The ratio of lengths of the two line segments formed on each transversal is the division of the lengths of the segments:
1st transversal: KL/LM
[tex]\frac{KL}{LM}=\frac{\sqrt{5}}{\sqrt{5}}=1[/tex]
2nd transversal: PO/ON
[tex]\frac{PO}{ON}=\frac{\sqrt{5.7986}}{\sqrt{5.7689}}\approx1[/tex]The ratios are the same (1) in pair of segments in each transversal