First we are going to calculate the height of the triangle using the right triangle that is formed:
We use the sine to calculate the leg opposite the angle:
[tex]\begin{gathered} sin\theta=\frac{opposite}{hypotenuse} \\ sin(27º)=\frac{VX}{13m} \\ VX=sin(27º)\cdot(13m) \\ VX=(0.454)\cdot(13m) \\ VX=5.9m \end{gathered}[/tex]
To calculate the area we use the equation for the area of the triangle:
[tex]\begin{gathered} A=\frac{b\cdot h}{2} \\ b=26m \\ A=\frac{26m(5.9m)}{2} \\ A=\frac{153.4m^2}{2} \\ A=76.7m^2 \end{gathered}[/tex]
