Question

Given j(k) = 4/3K2 – 7k + 1, find the value of J(-12).

Answer 1

EXPLANATION:

To find the value of j, we must plug the value given by the exercise for j into both equations;

So the exercise is as follows:

$\begin{gathered} j=\frac{4}{3k^2}-7k+1 \\ j=\frac{4}{3(-12)}-7(-12)+1 \\ j=\frac{4}{-36}-7(-12)+1 \\ j=\frac{4}{-36}+84+1 \\ j=\frac{4}{-36}+85 \\ j=\frac{340}{-36} \\ j=-9.4 \\ \text{the answer is -9.4} \end{gathered}$