The given expression are :
[tex]17>3x\text{ + 5 or 26}\leq3x+5[/tex]Simplify the first one :
[tex]\begin{gathered} 17>3x\text{ + 5} \\ \text{Subtract 17 from both side :} \\ 17-17>3x+5-17 \\ 0>3x-12 \\ add\text{ 12 on both side :} \\ 0+12>3x-12+12 \\ 12>3x \\ \text{Divide both side by 3 :} \\ \frac{12}{3}>\frac{3x}{3} \\ 4>x \end{gathered}[/tex]Now simplify the second one :
[tex]\begin{gathered} 26\leq3x+5 \\ \text{Subtract 5 on both side :} \\ 26-5\leq3x+5-5 \\ 21\leq3x \\ \text{Divide both side by 3 :} \\ \frac{21}{3}\leq\frac{3x}{3} \\ 7\leq x \end{gathered}[/tex]So, the x will be :
[tex]\begin{gathered} 4>x\text{ or 7}\leq x \\ \text{ Notation : 4>}x\ge7 \end{gathered}[/tex]To plot on the number line :
