Question

multiple (-3/4b^2)(-6a^2b^5) simplify your answer. use intergers or improper fraction for any numbers in the expression

Answer 1

we have (-3/4b^2)(-6a^2b^5)

so

$\frac{-3b^2}{4}\cdot-6a^2b^5=(-\frac{3}{4}\cdot-6)\cdot a^2b^7=\frac{18}{4}\cdot a^2b^7$

simplify

$\frac{9}{2}a^2b^7$