Question

You spin a spinner with 9 equal spaces numbered 1 through 9. What is the probability that the spinner lands on a 5.answers 7/98/91/92/9

Answer 1

$Pr(\text{event)}=\frac{number\text{ of favourable/possible outcomes}}{\text{total number of outcomes}}$$Pr(\text{spinner lands on 5)=}\frac{1}{9}$

Hence, the correct option is Option C