Question

What would the molarity of a NaOH solution that was made by taking 45.5 mL of 0.875 M NaOH and then diluting with water to a total volume of 500 mL?

Answer 1

Answer:

0.0796M

Explanation;

Using the dilution formula:

$C_1V_1=C_2V_2$

where:

C1 and C2 are the initial and final concentration

V1 and V2 are the initial and final volume

Given the following parameters

C1 = 0.875M

V1 = 45.5mL

V2 = 500mL

Required

Final concentration C2

Substituting the given parameters into the formula

$\begin{gathered} C_2=\frac{C_1V_1}{V_2} \\ C_2=\frac{0.875\times45.5mL}{500mL} \\ C_2=\frac{39.8125}{500} \\ C_2=0.0796M \end{gathered}$

Hence the final concentration is 0.0796M