In the given figure, the tunnel is in the shape of a cylinder.
The diameter of the tunnel, D=4 ft
Hence, the radius of the tunnel is,
[tex]r=\frac{D}{2}=\frac{4}{2}=2\text{ ft}[/tex]
The height of the cubical block, a=6 ft.
The height of the tunnel is the same as the height of the cubical block.
Hence, the height of the tunnel, h=a=6 ft.
Now, the volume of the tunnel in the shape of a cylinder can be calculated as,
[tex]\begin{gathered} V=\pi r^2h \\ =\pi\times2^2\times6 \\ =75.4ft^2 \end{gathered}[/tex]
Therefore, the volume of the tunnel created inside the block is 75.4 sq.ft.
