What is twice the difference of a number and 4 is equal to three Times a sum of the number 3

Let us represent the unknown number using the variable x.
The difference of the number and 4 is represented by x - 4.
Twice their difference would be 2(x - 4).
The sum of the same number and 3 is represented by x + 3.
Three times their sum is then represented by 3(x + 3).
The complete equation is then:
[tex]2(x-4)=3(x+3)[/tex]To solve for the unknown number, let's simplify using the properties of equality.
[tex]\begin{gathered} 2(x-4)=3(x+3) \\ \\ 2x-8=3x+9 \\ \\ 2x-3x=9+8 \\ \\ -x=17 \\ \\ x=-17 \end{gathered}[/tex]The missing number is -17.