Question

Find the error(s) and solve the problem correctly. Question: Determine the type(s) of the triangle with the given coordinates. X(6,1) Y(-2,-3) Z(0,3)

Answer 1

In the given computation, the error is in solving the distance of XZ. The square of -2 is not -4 for but +4.

The correct computation will be:

$\begin{gathered} \text{ XZ = }\sqrt[]{(6-0)^2+(1-3)^2\text{ }} \\ \text{ XZ = }\sqrt[]{(6)^2+(-2)^2} \\ \text{ XZ = }\sqrt[]{36\text{ + 4}} \\ \text{ XZ = }\sqrt[]{40} \end{gathered}$

Therefore, according to the correct calculations, the triangle is an isosceles triangle.