Question

Write an equation of a line that would be perpendicular to y =-x-8

Answer 1

Let:

$y=-x-8$

From that equation:

$m1=-1$

If two lines are perpendicular, then:

$\begin{gathered} m1\times m2=-1 \\ m2=1 \end{gathered}$

Given an arbitraty point:

$(x1,y1)=(1,2)$

Using the point slope equation:

$\begin{gathered} y-y1=m(x-x1) \\ y-2=1(x-1) \\ y-2=x-1 \\ y=x+1 \end{gathered}$