Question

If (3x−7)/(5>−7x−4)/3, what is the least integer value of x?

Answer 1

$\frac{3x-7}{5}>\frac{-7x-4}{3}$

start by bringing the denominators of both fractions to the other side

$3(3x-7)>5(-7x-4)$

Distribute the factors

$9x-21>-35x-20$

move al constants to one side and the variables to the other

$9x+35x>-20+21$

simplify both sides

$44x>1$

divide by 44 on both sides

$x>\frac{1}{44}$