Question

If a car exerts -644 Newtons of force on the road, what will be the acceleration of the 1,371 kg vehicle?Ignore friction and air resistance. Round your answer to two decimal places.

Answer 1

,In this case we will use Newton's second law

$F=ma$

Where F is the force, m is the mass and a is the acceleration

In our case

F=-644 N

m=1,371 kg

a=?

$644=1371(a)$

We isolate the a

$a=\frac{-644}{1371}=-0.47m/s^2$

ANSWER

-0.47 m/s^2