The correct answer is 3.6×10⁷ (1/Ωm)
Given,
The length of the aluminum wire, l=5.5 m
The resistance of the wire, R=0.40 Ω
The resistivity of the wire, ρ=2.82×10⁻⁸ Ωm
The resistivity is given by the inverse of the conductivity of a material.
Thus the conductivity of the given wire is,
[tex]c=\frac{1}{\rho}[/tex]On substituting the known values,
[tex]\begin{gathered} c=\frac{1}{2.82\times10^{-8}} \\ =3.6\times10^7\text{ (1/}\Omega\text{m)} \end{gathered}[/tex]Therefore the conductivity of the given aluminum wire is (1/Ωm)
