Answer:
Writing the given equation in slope-intercept form we have;
[tex]\begin{gathered} y=\frac{x}{5}-\frac{3}{25} \\ or \\ y=\frac{1}{5}x-\frac{3}{25} \end{gathered}[/tex]Explanation:
Given the linear equation;
[tex]5x-25y=3[/tex]We want to turn the given linear equation to slope-intercept form.
[tex]\begin{gathered} y=mx+b \\ m=\text{slope} \\ b=y-\text{intercept} \end{gathered}[/tex]To do that, let us make y the subject of formula;
subtract 5x from both sides;
[tex]\begin{gathered} 5x-5x-25y=-5x+3 \\ -25y=-5x+3 \end{gathered}[/tex]divide both sides by -25 (the coefficient of y);
[tex]\begin{gathered} \frac{-25y}{-25}=\frac{-5x}{-25}+\frac{3}{-25} \\ y=\frac{x}{5}-\frac{3}{25} \end{gathered}[/tex]Therefore, writing the given equation in slope-intercept form we have;
[tex]y=\frac{x}{5}-\frac{3}{25}[/tex]