Let:
x = Speed of the boat downstream
y = Speed of the boat upstream
A river cruise boat sailed 120 miles down the Mississippi River for six hours. So:
[tex]\begin{gathered} 6(x+y)=120 \\ x+y=\frac{120}{6} \\ x+y=20_{\text{ }}(1) \end{gathered}[/tex]It took eight hours to return. So:
[tex]\begin{gathered} 8(x-y)=120 \\ x-y=\frac{120}{8} \\ x-y=15_{\text{ }}(2) \end{gathered}[/tex]Using elimination method:
[tex]\begin{gathered} (1)+(2) \\ x+x+y-y=20+15 \\ 2x=35 \\ x=\frac{35}{2} \\ x=17.5 \end{gathered}[/tex]Replace x into (2):
[tex]\begin{gathered} 17.5-y=15 \\ y=17.5-15 \\ y=2.5 \end{gathered}[/tex]Therefore, the rate of the cruise boat in still water is 17.5 mph and the rate of the current is 2.5mph