Question

Theresa morgan, a chemist, has a 10% hydrocloric acid solution and a 70% hydrocloric acid solution. How many liters of each should she mix to get 750 liters of hydrocloric acid solution with a 54% acid concentration?

Answer 1

Suppose she needs "x" liters of 10% acid and "y" liters of 70% acid.

Given,

$x+y=750$

or,

y = 750 - x

The end result should be 54% acid.

We can come up with an equation >>>>

$0.1x+0.7(750-x)=0.54(750)$

We can easily solve this equation for "x". The steps are outlined below:

$\begin{gathered} 0.1x+0.7(750-x)=0.54(750) \\ 0.1x+525-0.7x=405 \\ 0.7x-0.1x=525-405 \\ 0.6x=120 \\ x=\frac{120}{0.6} \\ x=200 \end{gathered}$

Now let's find "y":

$\begin{gathered} y=750-x \\ y=750-200 \\ y=550 \end{gathered}$

Thus,

The mixture should be

200 liters of 10% hydrochloric acid550 liters of 70% hydrochloric acid