Given:
[tex]p=\frac{2}{5}[/tex]
Therefore, evaluating the expressions below
b)
[tex]\begin{gathered} p^2-\frac{3}{25} \\ (\frac{2}{5})^2-\frac{3}{25}=\frac{4}{25}-\frac{3}{25}=\frac{4-3}{25}=\frac{1}{25} \\ \therefore\text{The answer is }\frac{1}{25}\text{.} \end{gathered}[/tex]
c)
[tex]\begin{gathered} (\frac{2}{10})^2\div p \\ (\frac{2}{10}\times\frac{2}{10})\div\frac{2}{5}=\frac{4}{100}\div\frac{2}{5}=\frac{4}{100}\times\frac{5}{2}=\frac{20}{200}=\frac{1}{10} \\ \therefore The\text{ answer is }\frac{1}{10}\text{.} \end{gathered}[/tex]
d)
[tex]\begin{gathered} 3p_{}+\frac{1}{15} \\ 3(\frac{2}{5})+\frac{1}{15}=\frac{6}{5}+\frac{1}{15}=\frac{6\times3+1}{15}=\frac{18+1}{15}=\frac{19}{15}=1\frac{4}{15} \\ \therefore The\text{ answer is }1\frac{4}{15}\text{.} \end{gathered}[/tex]
e)
[tex]\begin{gathered} 2p-p^2-\frac{2}{5} \\ 2(\frac{2}{5})-(\frac{2}{5})^2-\frac{2}{5}=\frac{4}{5}-\frac{4}{25}-\frac{2}{5}=\frac{4\times5-4-2\times5}{25}=\frac{20-4-10}{25}=\frac{6}{25} \\ \therefore The\text{ answer is }\frac{6}{25}\text{.} \end{gathered}[/tex]
