Question

The equation for photon energy, E , isE=hc/λ where h = 6.626×10^−34 J⋅s (Planck's constant) and c = 2.99×10^8 m/s (the speed of light).What is the wavelength, λ , of a photon that has an energy of E = 3.32×10^−19 J ?Express your answer numerically in meters.

Answer 1

The energy for a photon is given by the equation:

$E=\frac{hc}{\lambda}$

In this case the energy is 3.32e-19 J; plugging this value and solving for the wavelength we have:

$\begin{gathered} 3.32\times10^{-19}=\frac{(6.626\times10^{-34})(2.99\times10^8)}{\lambda} \\ \lambda=\frac{(6.626\times10^{-34})(2.99\times10^8)}{3.32\times10^{-19}} \\ \lambda=5.97\times10^{-7} \end{gathered}$

Therefore, the wavelength is:

$\lambda=5.97\cdot10^{-7}\text{ m}$