2. Solve for h: h 1 + 5 -3 2 = 17. o 5 h = – 3 -3 6 1 h= -67 2 -67 1 On- h = -34 2 On=-71 /

We are given the following expression:
[tex]\frac{h}{-3}+5\frac{1}{2}=17[/tex]We are asked to solve for "h". To do that we will first rewrite the mixed fraction in standard form:
[tex]\frac{h}{-3}+5+\frac{1}{2}=17[/tex]Now we add 5 and 1/2, we get:
[tex]\frac{h}{-3}+\frac{11}{2}=17[/tex]Now we subtract 11/2 from both sides:
[tex]\frac{h}{-3}=17-\frac{11}{2}[/tex]Now we solve the difference:
[tex]\frac{h}{-3}=\frac{23}{2}[/tex]Now we multiply both sides by -3:
[tex]h=-\frac{69}{2}[/tex]Now we rewrite the numerator as follows:
[tex]h=-\frac{68+1}{2}[/tex]Now we distribute the denominator:
[tex]h=-(\frac{68}{2}+\frac{1}{2})[/tex]Simplifying we get:
[tex]h=-(34+\frac{1}{2})[/tex]Now we can write the result as a mixed fraction:
[tex]h=-34\frac{1}{2}[/tex]And thus we have solved for "h".