We have two different plans
x is the number of minutes
y= total cost in dollars
Part A)
Plan 1
y=0.20x
Plan 2
y=0.09x+49.95
Part B
In order that the second plan will be preferable, is when the plan 2 is cheaper so we will have the next inequality
[tex]0.20x>0.09x+49.95[/tex]Then we need to solve the inequality
[tex]0.20x-0.09x>49.95[/tex][tex]0.11x>49.95[/tex][tex]x>\frac{49.95}{0.11}[/tex][tex]x>454.09[/tex]The nearest greater inter is 455
Therefore the minimum number of minutes you would have to use in a month in order for the second plan to be preferable is 455 minutes