a)
[tex]\begin{gathered} \theta\text{ = 35} \\ \text{opposite = Height} \\ \text{Adjacent = 32} \\ \tan \theta\text{ = }\frac{opposite}{\text{adjacent}} \\ \tan 35\text{ = }\frac{H}{32} \\ 0.7\text{ = }\frac{H}{32} \\ H=32\text{ x 0.7} \\ H\text{ = }22.4\text{ f}eet \end{gathered}[/tex]
b)
Hypotanuse = length of rafter = x
[tex]\begin{gathered} \cos \theta\text{ = }\frac{adjacent}{\text{hypotanuse}} \\ \cos \text{ 35 = }\frac{32}{x} \\ 0.819\text{ = }\frac{32}{x} \\ \text{Cross multiple} \\ 0.819x\text{ = 32} \\ \text{divide through by 0.819} \\ x\text{ = }\frac{32}{0.819} \\ x\text{ = 39.07 f}eet\text{ } \\ \\ \end{gathered}[/tex]
