The question is first given in percentages. However, the requirement is to find the actual weight of the substance.
Given the value of the weight of a single fraction in the combination, we can get the weights of the other samples.
We'll thus have:
[tex]0.05x+0.2(109-x)=0.143(109)[/tex]Next, we solve for x
[tex]\begin{gathered} 0.05x+21.8-0.2x=15.587 \\ 0.05x-0.2x=15.587-21.8 \\ -0.15x=-6.213 \\ \text{Divide both sides by -0.15} \\ x=41.42 \end{gathered}[/tex]ANS = 41.42