Question

- If a trinomial is in the form ax? + bx + c, where a = 1, then the pair of factors (m x n) that results to"'" and add up (m + n) to get the value of "b" will give you the factors (x + m) (x + n)

Answer 1

Explanation:

The given equation is:

$\begin{gathered} 5a^2+55a-90 \\ 5(a^2+11a-18) \end{gathered}$

To factorize, we will use the following equation:

$a=\frac{-c_2_{}\pm\sqrt[]{(c_2)^2-4(c_1)(c_3)}}{2(c_1)}$

Where c1 is the number besides a², c2 is the number beside a, and c3 is the constant.

Replacing c1 = 1, c2 = 11, and c3 = -18, we get:

$undefined$