Given:
[tex]tan(\frac{1}{2}x)+cot(\frac{1}{2}x)=2cscx[/tex]
To start you use the formula for a half angle identity for tan.
[tex]tan(\frac{1}{2}x)=\frac{1-cosx}{sinx}=\frac{sinx}{1+cosx}[/tex]
Cot is just the just 1/tan so we can just invert the half angle identity for tan.
[tex]cot(\frac{1}{2}x)=\frac{sinx}{1-cosx}=\frac{1+cosx}{sinx}[/tex]
Therefore we can have a multitude of answers. But the only one available for the choices given is:
[tex]\frac{1-cosx}{sinx}+\frac{sinx}{1-cosx}[/tex]
Answer:
1st one: I only