Question

In the equation x + 3y = 6, suppose the x-intercept was at (m, 0) and the y-intercept was at the ordered pair (0, n). What is the value of m + n?A. 6 + 2 = 8B. 3 + 1 = 4C. 6 + 3 = 9D. 0 + 0 = 0

Answer 1

$x+3y=6$

we will replace both points

(m,0)

$\begin{gathered} (m)+3(0)=6 \\ m=6 \end{gathered}$

the value of m is 6

(0,n)

$\begin{gathered} (0)+3(n)=6 \\ 3n=6 \\ n=\frac{6}{3}=2 \end{gathered}$

the value of n is 2

now m+n

$\begin{gathered} m+n \\ 6+2 \\ =8 \end{gathered}$

the solution is 8