Given:
[tex]\begin{gathered} f(x)=3x^2+1 \\ g(x)=3x-1 \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} (f+g)(x)=3x^2+1+(3x-1)=3x^2+1+3x-1=3x^2+3x+1-1=3x^2+3x \\ \therefore(f+g)(x)=3x^2+3x \end{gathered}[/tex]Let us now substitute x = 2
[tex]\begin{gathered} (f+g)(2)=3(2)^2+3(2)=3(4)+6=12+6=18 \\ \therefore(f+g)(2)=18 \end{gathered}[/tex]Hence,
[tex]\begin{equation*} (f+g)(2)=18 \end{equation*}[/tex]