Solution:
Recall that from trigonometric identities:
[tex]\tan(A-B)=\frac{\tan A-\tan B}{1+\tan A\tan B}[/tex]
Given:
This implies that by comparison,
[tex]\begin{gathered} A=43\degree \\ B=18\degree \end{gathered}[/tex]
Thus, we have
[tex]\begin{gathered} \tan(43-18) \\ =\tan25 \end{gathered}[/tex]
Hence, as a trigonometric function of one number, we have
[tex]\tan25[/tex]
