[tex]\begin{gathered} \text{The equation is,} \\ 4x-8y=36\ldots.(1) \\ \text{The x-value that is five times of y-value.} \\ So, \\ x=5y\ldots(2) \\ \text{Substitute the value from the equation (2) into the equation (1)} \\ 4(5y)-8y=36 \\ 20y-8y=36 \\ 12y=36 \\ y=3 \\ \text{Now, substitute the value of y=3 in the equation (2)} \\ x=5\times3=15 \\ \text{Thus, the solution is}\Rightarrow(15,3) \end{gathered}[/tex]
