Given:
1) A coin is tossed.
the number of outcomes is {H,T}=2.
2) Selecting the numbers from 0-9 then number of outcomes = 10.
The probability of getting head when a coin is tossed is given by,
[tex]\begin{gathered} P=\frac{desired\text{ outcomes}}{\text{total number of outcomes}} \\ P=\frac{1}{2} \end{gathered}[/tex]The probability of getting number 9 out of 10 possibility is,
[tex]P=\frac{1}{10}[/tex]Note that the given events are independant.
The probability of getting heads and a number 9 is,
[tex]\begin{gathered} P=\frac{1}{2}\times\frac{1}{10} \\ =\frac{1}{20} \\ =0.05 \end{gathered}[/tex]Hence, the probability is 0.05.
