Given:
The objective is to find the value of π√2+6π√2.
The given can term can be solved as,
[tex]\begin{gathered} =\pi\sqrt[]{2}+6\pi\sqrt[]{2} \\ =\pi\sqrt[]{2}(1+6) \\ =\pi\sqrt[]{2}(7) \\ =7\pi\sqrt[]{2} \\ =7\cdot\frac{22}{7}\sqrt[]{2} \\ =22\cdot\sqrt[]{2} \\ =31.117 \end{gathered}[/tex]Hence, the value of π√2+6π√2 is 31.117.
