Calculator the mass of iron (III) oxide ( Fe2O3) that contains a billion (1.0x10^9) oxygen atoms. Be sure your answer has a unit symbol if necessary, and round it to 2 significant digits

Calculator the mass of iron III oxide Fe2O3 that contains a billion 10x109 oxygen atoms Be sure your answer has a unit symbol if necessary and round it to 2 sig class=

Respuesta :

1)First, let's use the chemical formula of iron (III) oxide (Fe₂O₃) to find the number of molecules of Fe₂O₃.

So one molecule of iron oxide contains 2 atom of Fe and 3 atom of Oxygen.

So you might find that:

1 molecule of Fe₂O₃ ------ 3 atoms of Oxygen

x molecule of Fe₂O₃ ------ 1.0×10⁹ atoms of Oxygen

x = 1.0×10⁹/3

x = 3.3 × 10⁸ molecules of Fe₂O₃

2) Now you use the Avogrado's constant to transform molecules into moles.

6.022 × 10²³ molecules ----- 1 mol

3.3 × 10⁸ molecules of Fe₂O₃ ----- x mol

x = 3.3 × 10⁸/6.022 × 10²³

x = 5.5 × 10⁻¹⁶ moles of Fe₂O₃

3) Finally, let's use the molar mass of Fe₂O₃ to find out the mass.

Molar mass of Fe₂O₃: (2x55.9) + (3x16) = 159.8

159.8 g ----- 1 mol

x g ----- 5.5 × 10⁻¹⁶ moles of Fe₂O₃

x = 8.8 x 10^-14 grams

Answer: The mass of iron (III) oxide ( Fe2O3) that contains a billion (1.0x10^9) oxygen atoms is 8.8 x 10^-14 grams

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