Question

2. You roll a fair six-sided die twice. Find the probability of rolling a 2 the first time and a number greater than 3 the second time.

Answer 1

Notice that the event of rolling a 2 the first time and the event of rolling a number greater than 3 the second time are independents, therefore:

$P=P(2)\times P(x>3)\text{.}$

Computing P(2) and P(x>3) we get:

$\begin{gathered} P(2)=\frac{1}{6}, \\ P(x>3)=\frac{3}{6}=\frac{1}{2}._{} \end{gathered}$

Therefore:

$P=\frac{1}{6}\times\frac{1}{2}=\frac{1}{12}\text{.}$

Answer:

$\frac{1}{12}\text{.}$