A game spinner has regions that are numbered 1 through 8. If the spinner is used twice, what is the probability that the first number is a 3 and the second is a 6?A. 9/64B. 1/16C. 2/3D. 1/64

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to solve this problem, we shall solve the first probability and then multiply it by the second probability

probability that the first number is 3 is 1/8

probability that the second number is 6 is 1/8

note: in this type of probability, each time the spinner goes around, the probability of picking a particular number is 1 over the total number of regions in the spinner

therefore, the probability of the first number to be 3 and the second number 6 is

[tex]P(e)=P(3)\times P(6)=\frac{1}{8}\times\frac{1}{8}=\frac{1}{64}[/tex]

the answer to this question is option D

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