Let's begin by listing out the information given to us:
base 1 = 12m, base 2 = 13m, height = 9 1/2m
The volume of a triangular pyramid is given by:
[tex]\begin{gathered} v=\frac{1}{3}\cdot\frac{1}{2}Bh \\ B=b_1\cdot b_2=12\cdot13=156m^2,h=9\frac{1}{2}=\frac{19}{2}m \\ v=\frac{1}{3}\cdot\frac{1}{2}\cdot156\cdot\frac{19}{2}=247m^3 \\ v=247m^3 \end{gathered}[/tex]
