Question

An Australian Shepherd breeder has had three litters of puppies from the same set of parents. The following table shows the results from the three litters. In the next litter, whst is the probability of a puppy having no spots? Enter a fraction or round your answer to four decimal places if necessary Black and White = 7Red and White = 9Black with Spots =8Red with Spots = 5

Answer 1

Given:

Black and White are 7.

Red and White are 9.

Black with Spots is 8.

Red with Spots is 5​.

To find:

The probability of a puppy having no spots.

Explanation:

We know that,

The formula of the probability of an event is,

$P(E)=\frac{Number\text{ of favourable outcomes}}{Total\text{ number of outcomes}}$

The number of puppies having no spots is,

$7+9=16$

The total number of puppies is,

$7+9+8+5=29$

Therefore, the probability is,

$\frac{16}{29}$

Final answer:

The probability of a puppy having no spots is,

$\frac{16}{29}$