NadalieB699275 NadalieB699275
  • 29-10-2022
  • Mathematics
contestada

Figure 1 is a triangle with vertices at R(18, 6), S(12, 15), and T(3, 9). It is dilated, using the origin as the center with a scale factor of 2/3

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AbdulkarimD155488 AbdulkarimD155488
  • 29-10-2022

You have the following points for the vertices of a triangle:

R(18,2)

S(12,15)

T(3,9)

If the triangle is dilated with a factor 2/3 with the origin as reference, you simpliy add to each coordinate of each point the result of the product of the coordinate by the scale factor. You proceed as follow for each vertex:

R(18,2)

18 + 18(2/3) = 30

2 + 2(2/3) = 10/3

Then:

R'(30 , 10/3) "this is the dilated point for R"

S(12 ,15)

12 + 12(2/3) = 20

15 + 15(2/3) = 25

S'(20 , 25)

T(3,9)

3 + 3(2/3) = 5

9 + 9(2/3) = 15

T'(5 , 15)

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