We must write a logarithmic function with the following properties:
0. The range of the function is (−∞, ∞).
,1. The domain of the function is (−1, ∞).
,2. The vertical asymptote of the function is x = −1.
,3. The graph crosses through the origin.
To answer this question, first, we remember the parent logarithm function:
[tex]f(x)=\ln x,[/tex]which has
• range = (−∞, ∞),
,• domain = (0, ∞),
,• vertical asymptote at x = 0,
,• the value f(1) = 0.
Now, if we change the function in the following way:
[tex]g(x)=\ln (x+1)\text{.}[/tex]We see that now we have:
• range = (−∞, ∞),
,• domain = (-1, ∞),
,• vertical asymptote at x = -1,
,• the value g(0) = 0 → the graph crosses through the origin.
Answer
[tex]g(x)=\ln (x+1)[/tex]